本論文以中鋼燒結冷卻機熱回收系統作ㄧ性能分析，並以數值模擬方式配合實驗探討中鋼公司燒結礦冷卻之熱流場現象。由於燒結礦堆積內部結構複雜且呈不規則分布，故本文以流體流過ㄧ個充滿圓形粒子(particles)的packed beds來模擬燒結礦內部的流場，找出溫度與壓力隨著時間變化的情形，並以共軛熱傳來求解流體對固體(fluid-to-particles)和固體本身(particles)內部的熱傳現象。
在本文中物理模型可分為兩類，全尺寸模型與4-row模型，其中全尺寸模型為孔隙率Φ=0.38、粒度D=100。而4-row模型主要討論孔隙率分別為0.4與0.5，粒度則為50、70與100mm。另外為了將4-row模型與全尺寸模型作比較，因此在4-row模型中又添加了孔隙率為0.38、粒度為100mm的條件。
由數值結果發現，全尺寸模型之燒結礦體平均溫度在風速為1.2m/s的時候比入口風速為2m/s時平均熱傳係數 約提高40%。同孔隙率(Φ=0.4)下，粒度由100mm縮小到50mm時，平均熱傳係數 提高約10~20%。而在同粒度(D=70mm）下，孔隙率由0.5縮小到0.4，則平均熱傳係數 提高約30~40%。在孔隙率0.38，粒度100mm的情形下，全尺寸與4-row模型的平均熱傳係數僅僅相差3%。
將模擬得到的結果作回歸分析，可以得到h=h(D,Φ,Re)之關係式：h=KfD(8.75+0.013Re^0.896)/(ΦD)，此式適用在雷諾數Re為1300~11000之間。利用此式之熱傳係數所得到的溫度與實驗作比較，燒結礦的溫度誤差在10%以內，而空氣溫度的誤差則小於30%。

A 3-D numerical model was performed in the study to simulate the cooling process and enabled the transient analysis of the moving bed. This study also presents the local flow field and the conjugated heat transfer between the fluid and solid in the packed bed. The experimental data was obtained from the iron-ore sinter bed of the China-Steel Company and compared with the numerical results in the study.
Two kinds of models, full scale and 4-rows model were used and analyzed in the study. For the full scale model, the porosityΦ=0.38 and particle diameter D=100mm were applied and discussed. To simplified the model and reduced the computer time, the 4-rows model was performed and two different porosity (Φ=0.4 and 0.5) and three different particle diameter (D=50mm, 70mm and 100mm) were applied and discussed.
From the numerical results, the average heat transfer coefficient was about 40% higher when the inlet speed was varied from 1.2m/s to 2m/s. For the same porosity, the average heat transfer coefficient was increased 10%~20% when the particle diameter reduced form 100mm to 50mm. From the same particle diameter, the average heat transfer coefficient was increased 30%~40% when the porosity was reduced from 0.5 to 0.4. The numerical results of the sinter and air temperature agreed with the experimental data within 10%and 30%. The equation for the heat transfer coefficient h is h=KfD(8.75+0.013Re^0.896)/(ΦD)
Which gives an error form 3.6% to 8.7% over the entire range of Re.

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