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研究生: 潘政揚
Pan, Cheng-Yang
論文名稱: Femtocell無線網路收益成本之提升
Enhancing Revenue and Expenditure in Wireless Networks of Femtocell System
指導教授: 郭文光
Kuo, Wen-Kuang
學位類別: 碩士
Master
系所名稱: 電機資訊學院 - 電腦與通信工程研究所
Institute of Computer & Communication Engineering
論文出版年: 2016
畢業學年度: 104
語文別: 中文
論文頁數: 36
中文關鍵詞: Femtocell收益成本CCT轉換分枝定限法
外文關鍵詞: Femtocell, Revenue and Expenditure, Charnes-Cooper Transformation, Branch and Bound
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  • 手持裝置日漸普及,使用者對於傳輸速率的需求愈來愈高,傳統的基地台漸漸無法滿足大眾的需求。Femtocell無線基地台因此誕生。成本低、容易部署、耗電量低、覆蓋率佳的特性,使得Femtocell近年來逐漸獲得業界的重視。本論文建立了此網路架構。假設一個系統模型模擬Femtocell無線基地台的收益成本狀況。由於此系統模型的數學式複雜度過高,我們使用CCT轉換將原問題由線性分數規劃轉換成線性規劃並簡化數學式。最後使用最佳化演算法-分枝定限法求得收益成本問題的最佳解。

    The growing popularity of handset devices, user demand for higher and higher transmission rate, the traditional base station gradually unable to meet the needs of the public. Therefore, Femtocell was born. low cost, easy to deploy, low power consumption, excellent coverage, with these property, making Femtocell gradually in recent years by the industry’s attention. In this paper, we establish this network architecture. Assuming a system model to simulate the revenue and expenditure of Femtocell. Due to the mathematical formula of this complex system model is too high, we use Charnes-Cooper Transformation to convert the original problem which is linear-fractional programming into linear programming and simplifies the mathematical formula.
    Finally, using the optimization algorithm-Branch and Bound to find the best solution of the revenue and expenditure problem.

    目錄 第一章 序論 1 1.1 Femtocell簡介 1 1.2 研究動機與目的 3 1.3 文獻回顧 4 第二章 網路架構 5 2.1 3G W-CDMA ( UMTS ) 網路系統介紹 5 2.2 系統模型 6 2.3 數學模型 7 2.3.1 測試點與基地台之連結數量限制條件 7 2.3.2 基地台啟用限制條件 8 2.3.3 功率限制條件 8 2.3.4 功率總和限制條件 9 2.3.5 傳輸距離限制條件 9 2.3.6 通道容量限制條件 9 2.3.7 最小利潤限制條件 10 2.3.8 目標函式 11 第三章 求解程序 12 3.1 簡化數學模型 12 3.1.1 CCT轉換 12 3.1.2 簡化通道容量限制式 14 3.1.3 簡化二元整數限制式 17 3.2 分枝定限演算法 17 3.2.1 基本方法 17 3.2.2 求解步驟 18 第四章 數據模擬 19 4.1 參數設定 19 4.2 模擬結果 21 4.2.1 拓樸模擬數據一 ( TP = 9 ) 21 4.2.2 拓樸模擬數據二 ( TP = 12 ) 24 4.2.3 拓樸模擬數據三 ( TP = 15 ) 27 4.2.4 拓樸模擬數據四 ( TP = 18 ) 30 4.2.5 結果分析 33 第五章 結論 34

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